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Aptitude Online Test Set 1
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Question 1 of 21
1. Question
1 pointsWhat least number must be added to 1056, so that the sum is completely divisible by 23 ?
Correct
Incorrect
23) 1056 (45
92
—
136
115
—
21
—Required number = (23 – 21)
= 2. 
Question 2 of 21
2. Question
1 pointsA worker covered a distance of 61 km in 9 hours. He traveled partly on public transport at 4 km/hr and partly on auto at 9 km/hr. What is the distance traveled on public transport?
Correct
correct
Incorrect
wrong
Hint
Let the distance travelled on public transport be x km
Then, distance travelled on auto = (61 – x) km
So,x
4+
(61 – x)
9= 9
9x + 4(61 – x) = 9
x = 16 km 
Question 3 of 21
3. Question
1 pointsFather is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit’s age. After further 8 years, how many times would he be of Ronit’s age?
Correct
correct
Incorrect
incorrect

Question 4 of 21
4. Question
1 pointsFind the H.C.F. of 2^{3 }X 3^{2 }X 5 X 7^{4}, 2^{2 }X 3^{5} X 5^{2 }X 7^{3},2^{3 }X 5^{3 }X 7^{2}
Correct
correct
Incorrect
wrong
Hint
The prime numbers common to given numbers are 2,5 and 7.
H.C.F. = 2^{2} x 5 x7^{2} = 980.

Question 5 of 21
5. Question
1 pointsFind the average of all prime numbers between 30 and 50?
Correct
Incorrect
Hint

Question 6 of 21
6. Question
1 pointsRajeev’s age after 15 years will be 5 times his age 5 years back. What is the
present age of Rajeev ?
Correct
correct
Incorrect
wrong
Hint
Let Rajeev’s present age be x years. Then,
Rajeev’s age after 15 years = (x + 15) years.
Rajeev’s age 5 years back = (x – 5) years.
:. x + 15 = 5 (x – 5)
x + 15 = 5x – 25
4x = 40
x = 10.
Hence, Rajeev’s present age = 10 years.

Question 7 of 21
7. Question
1 pointsWhat is the quotient when (x^{1} – 1) is divided by (x – 1) ?
Correct
Incorrect
Hint

Question 8 of 21
8. Question
1 pointsAn inspector rejects 0.08% of the meters as defective. How many will be examine to project ?
Correct
Incorrect
Hint
Sol. Let the number of meters to be examined be x.
Then, 0.08% of x =2
[(8/100)*(1/100)*x] = 2
x = [(2*100*100)/8] = 2500

Question 9 of 21
9. Question
1 pointsA man buys an article for rs.27.50 and sells it for rs.28.50. find his gain %.
Correct
Incorrect
Hint
sol.
cp=rs27.50, sp=rs 28.50
gain=rs(28.50 –27.50)=rs1.10
so gain%={(1.10/27.50)*100}=4%

Question 10 of 21
10. Question
1 pointsIf x : y = 3 : 4, find (4x + 5y) : (5x – 2y).
Correct
Incorrect
Hint
Sol. X/Y=3/4 ó (4x+5y)/(5x+2y)= (4( x/y)+5)/(5 (x/y)2) =(4(3/4)+5)/(5(3/4)2)
=(3+5)/(7/4)=32/7

Question 11 of 21
11. Question
1 pointsAlfred started a business investing Rs. 45,000. After 3 months, Peter joined him with a capital of Rs. 60,000. After another 6 months, Ronald joined them with a capital of Rs. 90,000. At the end of the year, they made a profit of Rs. 16,500. Find the lire of each
Correct
Incorrect
Hint
Sol. Clearly, Alfred invested his capital for 12 months, Peter for 9 months and Ronald
for 3 months.
So, ratio of their capitals = (45000 x 12) : (60000 x 9) : (90000 x 3)
= 540000 : 540000 : 270000 = 2 : 2 : 1.
Alfred’s share = Rs. (16500 x (2/5)) = Rs. 6600
Peter’s share = Rs. (16500 x (2/5)) = Rs. 6600
Ronald’s share = Rs. (16500 x (1/5)) = Rs. 3300.

Question 12 of 21
12. Question
1 pointsIf 15 toys cost Rs, 234, what do 35 toys cost?
Correct
Incorrect
Hint
Sol. Let the required cost be Rs. x. Then,
More toys, More cost (Direct Proportion)
. 15 : 35 : : 234 : x ó (15 x x) = (35 x 234) ó x=(35 X 234)/15 =546
Hence, the cost of 35 toys is Rs. 546.

Question 13 of 21
13. Question
1 pointsArrange the fractions 5/8, 7/12, 13/16, 16/29 and 3/4 in ascending order of magnitude
Correct
Incorrect
Hint
Sol. Converting each of the given fractions into decimal form, we get :
5/8 = 0.624, 7/12 = 0.8125, 16/29 = 0.5517, and 3/4 = 0.75
Now, 0.5517<0.5833<0.625<0.75<0.8125
16/29 < 7/12 < 5/8 < 3/4 < 13/16

Question 14 of 21
14. Question
1 pointsTwo pipes A and B can fill a tank in 36 bours and 46 bours respectively. If both the pipes are opened simultaneously, how much time will be taken to fill the tank ?
Correct
Incorrect
Hint
Part filled by A in 1 hour = (1/36);
Part filled by B in 1 hour = (1/45);
Part filled by (A + B) In 1 hour =(1/36)+(1/45)=(9/180)=(1/20)
Hence, both the pipes together will fill the tank in 20 hours.

Question 15 of 21
15. Question
1 pointsA train 100 m long is running at the speed of 30 km / hr. Find the time taken by it to pass a man standing near the railway line.
Correct
Incorrect
Hint
Sol. Speed of the train = (30 x 5/18) m / sec = (25/3) m/ sec.
Distance moved in passing the standing man = 100 m.
Required time taken = 100/(25/3) = (100 *(3/25)) sec = 12 sec

Question 16 of 21
16. Question
1 pointsA man can row upstream at 7 kmph and downstream at 10 kmph.find man’s rate in still water and the rate of current.
Correct
Incorrect
Hint
Sol. Rate in still water=1/2(10+7)km/hr=8.5 km/hr.
Rate of current=1/2(107)km/hr=1.5 km/hr.

Question 17 of 21
17. Question
1 pointsIn what ratio must rice at Rs. 9.30 per kg be mixed with rice at Rs. 10.80 per kg so that the mixture be worth Rs. 10 per kg ?
Correct
Incorrect
Hint

Question 18 of 21
18. Question
1 pointsFind the simple interest on Rs. 68,000 at 16 2/3% per annum for 9 months.
Correct
Incorrect
Hint

Question 19 of 21
19. Question
1 pointsFind compound interest on Rs. 7500 at 4% per annum for 2 years, compounded annually.
Correct
Incorrect
Hint

Question 20 of 21
20. Question
1 pointsSimplify: b[b(a+b){b(bab)}+2a]
Correct
Incorrect
Hint
Sol. Given expression=b[b(a+b){b(ba+b)}+2a]
=b[bab{b2b+a}+2a]
=b[a{b2b+a+2a}]
=b[a{b+3a}]=b[a+b3a]
=b[4a+b]=b+4ab=4a

Question 21 of 21
21. Question
1 pointsOne side of a rectangular field is 15 m and one of its diagonals is 17 m. Find the area of the field.
Correct
Incorrect
Hint
Sol. Other side = ((17) ^{2}– (15)^{2)(1/2}) = (289 225)^{(1/2)} = (64)^{(1/2)} = 8 m.
Area = (15 x 8) m^{2} = 120 m^{2}.
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Aptitude Online Test Set 2
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Question 1 of 20
1. Question
1 points(112 x 5^{4}) = ?
Correct
Incorrect
(112 x 5^{4}) = 112 x 10 4 = 112 x 10^{4} = 1120000 = 70000 2 2^{4} 16 
Question 2 of 20
2. Question
1 points(112 x 5^{4}) = ?
Correct
Incorrect
(112 x 5^{4}) = 112 x 10 4 = 112 x 10^{4} = 1120000 = 70000 2 2^{4} 16 
Question 3 of 20
3. Question
1 pointsIn the air, sound moves at a rate of 1100 feet per second. A boy hears the temple’s bell sound 2.2 seconds after he sees it ringing. Find the distance of the man from the temple?
Correct
correct
Incorrect
wrong
Hint
Distance = 1100 x 2.2 = 2420 feet

Question 4 of 20
4. Question
1 pointsFind the H.C.F. of 108, 288 and 360.
Correct
correct
Incorrect
wrong
Hint
. 108 = 2^{2} x 3^{3}, 288
= 2^{5} x 3^{2 }and 360 = 2^{3 }x 5 x 3^{2}.
H.C.F. = 2^{2 }x 3^{2 }= 36.

Question 5 of 20
5. Question
1 pointsA and B together can complete a piece of work in 4 days. If A alone can complete the same work in 12 days, in how many days can B alone complete that work?
Correct
Incorrect
Hint
(A + B)’s 1 day’s work = (1/4). A’s 1 day’s work = (1/12).
B’s 1 day’s work =((1/4)(1/12))=(1/6)
Hence, B alone can complete the work in 6 days.

Question 6 of 20
6. Question
1 pointsfind the average of first 40 natural numbers?
Correct
Incorrect
Hint

Question 7 of 20
7. Question
1 pointsRajeev’s age after 15 years will be 5 times his age 5 years back. What is the
present age of Rajeev ?
Correct
correct
Incorrect
wrong
Hint
Let Rajeev’s present age be x years. Then,
Rajeev’s age after 15 years = (x + 15) years.
Rajeev’s age 5 years back = (x – 5) years.
:. x + 15 = 5 (x – 5)
x + 15 = 5x – 25
4x = 40
x = 10.
Hence, Rajeev’s present age = 10 years.

Question 8 of 20
8. Question
1 pointsIf 2^{x – 1} + 2^{x + 1} = 1280, then find the value of x.
Correct
Incorrect
Hint

Question 9 of 20
9. Question
1 pointsSixty five percent of a number is 21 less than four fifth of that number. What is the number ?
Correct
Incorrect
Hint
Sol. Let the number be x.
Then, 4*x/5 –(65% of x) = 21
4x/5 –65x/100 = 21
5 x = 2100
x = 140.

Question 10 of 20
10. Question
1 points. If the a radio is sold for rs 490 and sold for rs 465.50.find loss%
Correct
Incorrect
Hint
sol. cp=rs490,sp= 465.50.
loss=rs(490465.50)=rs 24.50.
loss%=[(24.50/490)*100]%=5%

Question 11 of 20
11. Question
1 pointsDivide Rs. 1162 among A, B, C in the ratio 35 : 28 : 20
Correct
Incorrect
Hint
Sum of ratio terms = (35 + 28 + 20) = 83.
A’s share = Rs. (1162 x (35/83))= Rs. 490; B’s share = Rs. (1162 x(28/83))= Rs. 392;
C’s share = Rs. (1162 x (20/83))= Rs. 280.

Question 12 of 20
12. Question
1 pointsIf 36 men can do a piece of work in 25 hours, in how many hours will 15 men
do it ?
Correct
Incorrect
Hint
Sol. Let the required number of hours be x. Then,
Less men, More hours (Indirect Proportion)
15 : 36 : : 25 : x ó(15 x x) = (36 x 25) ó(36 x 25)/15 = 60
Hence, 15 men can do it in 60 hours

Question 13 of 20
13. Question
1 pointsArrange the fractions 3/5, 4/7, 8/9, and 9/11 in their descending order
Correct
Incorrect
Hint
Sol. Clearly, 3/5 = 0.6, 4/7 = 0.571, 8/9 = 0.88, 9/111 = 0.818.
Now, 0.88 > 0.818 > 0.6 > 0.571
8/9 > 9/11 > 3/4 > 13/ 16

Question 14 of 20
14. Question
1 pointsTwo pipes can fill a tank in 10 hours and 12 hours respectively while a third, pipe empties the full tank in 20 hours. If all the three pipes operate simultaneously, in how much time will the tank be filled?
Correct
Incorrect
Hint
Net part filled In 1 hour =(1/10)+(1/12)(1/20)=(8/60)=(2/15).
The tank will be full in 15/2 hrs = 7 hrs 30 min.

Question 15 of 20
15. Question
1 pointsA train is moving at a speed of 132 km/br. If the length of the train is 110 meters, how long will it take to cross a railway platform 165 meters long?
Correct
Incorrect
Hint

Question 16 of 20
16. Question
1 pointsA man takes 3 hours 45 minutes to row a boat 15 km downstream of a river and 2hours30minutes to cover a distance of 5km upstream. find the speed of the river current in km/hr.
Correct
Incorrect
Hint

Question 17 of 20
17. Question
1 pointsHow much water must be added to 60 liters of milk at 1 ½ liters for Rs. 2 So as to have a mixture worth Rs.10 2/3 a liter ?
Correct
Incorrect
Hint

Question 18 of 20
18. Question
1 pointsFind the simple interest on Rs. 3000 at 6 1/4% per annum for the period from 4th Feb., 2005 to 18th April, 2005.
Correct
Incorrect
Hint
Remark : The day on which money is deposited is not counted while the day on which money is withdrawn is counted .

Question 19 of 20
19. Question
1 pointsFind compound interest on Rs. 8000 at 15% per annum for 2 years 4 months, compounded annually.
Correct
Incorrect
Hint

Question 20 of 20
20. Question
1 pointsWhat value will replace the question mark in the following equation?
4 1/2 + 3 1/6+ ? +2 1/3= 13 2/5
Correct
Incorrect
Hint
Sol. Let 9/2+19/6+x+7/3=67/5
Then x=(67/5)(9/2+19/6+7/3)óx=(67/5)((27+19+14)/6)=((67/5)(60/6)
óx=((67/5)10)=17/5=3 2
5
Hence, missing fractions =3 2/5
Time : 20 Minute , No of Questions20
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Aptitude Online Test Set 3
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Question 1 of 20
1. Question
1 pointsWhich one of the following is not a prime number?
Correct
Incorrect
91 is divisible by 7. So, it is not a prime number.

Question 2 of 20
2. Question
1 pointsWhich one of the following is not a prime number?
Correct
Incorrect
91 is divisible by 7. So, it is not a prime number.

Question 3 of 20
3. Question
1 pointsAlok runs around a circular field at a rate of 6 rounds per hour whereas Bina walks around the same field at the rate of 1 round per hour. If both started in the same direction from the same point at 7:30 AM then at what time they will first cross each other?
Correct
correct
Incorrect
wrong
Hint
Relative speed of Simran w.r.t Anita = 6 – 1 = 5 rounds per hour
Time taken to complete one round at this speed =1
5= 12 min

Question 4 of 20
4. Question
1 pointsReduce 391 to lowest terms .
667
Correct
correct
Incorrect
wrong
Hint
H.C.F. of 391 and 667 is 23.
On dividing the numerator and denominator by 23, we get :
391 = 391 / 23 = 17
667 667/ 23 29

Question 5 of 20
5. Question
1 pointsA and B can do a piece of work in 18 days; Band C can do it in 24 days A and C can do it in 36 days. In how many days will A, Band C finish it together and separately?
Correct
Incorrect
Hint
(A + B)’s 1 day’s work = (1/18)
(B + C)’s 1 day’s work = (1/24)
and (A + C)’s 1 day’s work = (1/36)
Adding, we get: 2 (A + B + C)’s 1 day’s work =(1/18 + 1/24 + 1/36)
=9/72 =1/8
(A +B + C)’s 1 day’s work =1/16
Thus, A, Band C together can finish the work in 16 days.
Now, A’s 1 day’s work = [(A + B + C)’s 1 day’s work] – [(B + C)’s 1 day work:
=(1/16 – 1/24)= 1/48
A alone can finish the work in 48 days.
Similarly, B’s 1 day’s work =(1/16 – 1/36)=5/144
B alone can finish the work in 144/5=28 4/5 days
And C’s 1 day work =(1/161/18)=1/144
Hence C alone can finish the work in 144 days.

Question 6 of 20
6. Question
1 pointsThe average of four consecutive even numbers is 27. find the largest of these numbers ?
Correct
Incorrect
Hint

Question 7 of 20
7. Question
1 pointsThe product of the ages of Ankit and Nikita is 240. If twice the age of Nikita
is more than Ankit’s age by 4 years, what is Nikita’s age?
Correct
correct
Incorrect
incorrect
Hint

Question 8 of 20
8. Question
1 pointsFind the Value of {(16)^{3/2} + (16)^{3/2}}
Correct
Incorrect
Hint

Question 9 of 20
9. Question
1 pointsIn expressing a length 810472 km as nearly as possible with three significant digits , find the percentage error
Correct
Incorrect
Hint
Sol. Error = (81.5 – 81.472)km = 0.028.
Required percentage = [(0.028/81.472)*100]% = 0.034%.

Question 10 of 20
10. Question
1 pointsFind S.P when CP=rs 80.40,loss=5%
Correct
Incorrect
Hint
sol: sp=85% of rs 80.40
=rs {(85/100)*80.40}=rs 68.34.

Question 11 of 20
11. Question
1 pointsA mixture contains alcohol and water in the ratio 4 : 3. If 5 litres of water is added to the mixture, the ratio becomes 4: 5. Find the quantity of alcohol in the given mixture
Correct
Incorrect
Hint
Sol. Let the quantity of alcohol and water be 4x litres and 3x litres respectively
4x/(3x+5)=4/5 ó20x=4(3x+5)ó8x=20 óx=2.5
Quantity of alcohol = (4 x 2.5) litres = 10 litres.

Question 12 of 20
12. Question
1 pointsIf 20 men can build a wall 66 metres long in 6 days, what length of a similar can be built by 86 men in 8 days?
Correct
Incorrect
Hint
Sol. Let the required length be x metres
More men, More length built (Direct Proportion)
Less days, Less length built (Direct Proportion)
Men 20: 35
Days 6: 3 : : 56 : x
Therefore (20 x 6 x x)=(35 x 3 x 56)óx=(35 x 3 x 56)/120=49
Hence, the required length is 49 m

Question 13 of 20
13. Question
1 pointsEvaluate : 5.064 + 3.98 + 0.7036 + 7.6 + 0.3 + 2
Correct
Incorrect
Hint
5.064
3.98
0.7036
7.6
0.3
_2.0___
19.6476

Question 14 of 20
14. Question
1 pointsAn electric pump can fill a tank in 3 hours. Because of a leak in ,the tank it took 3(1/2) hours to fill the tank. If the tank is full, how much time will the leak take to empty it ?
Correct
Incorrect
Hint
Sol: work done by the leak in 1 hour=(1/3)(1/(7/2))=(1/3)(2/7)=(1/21).
The leak will empty .the tank in 21 hours.

Question 15 of 20
15. Question
1 pointsA train 150 m long is running with a speed of 68 kmph. In what time will it pass a man who is running at 8 kmph in the same direction in which the train is going?
Correct
Incorrect
Hint

Question 16 of 20
16. Question
1 pointsThere is a road beside a river.two friends started from a place A,moved to a temple situated at another place B and then returned to A again.one of them moves on a cycle at a speed of 12 km/hr,while the other sails on a boat at a speed of 10 km/hr.if the river flows at the speed of 4 km/hr,which of the two friends will return to placeA first?
Correct
Incorrect
Hint

Question 17 of 20
17. Question
1 pointsHow many kgs. of wheat costing Rs. 8 per kg must be mixed with 86 kg of rice costing Rs. 6.40 per kg so that 20% gain may be obtained by Belling the mixture at Rs. 7.20 per kg ?
Correct
Incorrect
Hint

Question 18 of 20
18. Question
1 pointsA sum of Rs. 800 amounts to Rs. 920 in 8 years at simple interest rate is increased by 8%, it would amount to how much ?
Correct
Incorrect
Hint

Question 19 of 20
19. Question
1 pointsFind the compound interest on Rs. 16,000 at 20% per annum for 9 months, compounded quarterly.
Correct
Incorrect
Hint

Question 20 of 20
20. Question
1 pointsCorrect
Incorrect
Hint
Sol. Given exp. =[13/4¸{5/41/2(5/2(32)/12)}]=[13/4¸{5/41/2(5/21/12)}]
=[13/4¸{5/41/2((301)/12)}]=[13/4¸{5/429/24}]
=[13/4¸{(3039)/24}]=[13/4¸1/24]=[(13/4)*24]=78
Time : 20 Minute , No of Questions20
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Aptitude Online Test Set 4
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Question 1 of 20
1. Question
1 pointsA student has 5 pants and 4 shirts .how many way he has to go school for combination. ?
Correct
Incorrect
Hint
combination =5×4 =20

Question 2 of 20
2. Question
1 pointsWhich one of the following is not a prime number?
Correct
Incorrect
91 is divisible by 7. So, it is not a prime number.

Question 3 of 20
3. Question
1 pointsWhich one of the following is not a prime number?
Correct
Incorrect
91 is divisible by 7. So, it is not a prime number.

Question 4 of 20
4. Question
1 pointsWhat is the time taken by a man to run around a rectangular field of dimension 33 meters by 37 meters, if he runs at the speed of 6 km/hr?
Correct
correct
Incorrect
wrong
Hint
Speed = 6 km/hr = 6x
5
18m/sec = 2.5 m/sec
Distance = 2x(33 + 37) = 140 m
Time taken =140
2.5= 56sec

Question 5 of 20
5. Question
1 pointsFind the H.C.F. of 513, 1134 and 1215
Correct
correct
Incorrect
wrong
Hint
1134 ) 1215 ( 1
1134
81 ) 1134 ( 14
81
324
324
x
\H.C.F. of 1134 and 1215 is 81.
So, Required H.C.F. = H.C.F. of 513 and 81.
______
81 ) 513 ( 6
__486____
27) 81 ( 3
81
0
H.C.F. of given numbers = 27.

Question 6 of 20
6. Question
1 pointsA can do a piece of work in 7 days of 9 hours each and B can do it in 6 days of 7 hours each. How long will they take to do it, working together 8 hours a day ?
Correct
Incorrect
Hint
A can complete the work in (7 x 9) = 63 hours.
B can complete the work in (6 x 7) = 42 hours.
A’s 1 hour’s work = (1/63) and B’s 1 hour’s work =(1/42)
(A + B)’s 1 hour’s work =(1/63)+(1/42)=(5/126)
Both will finish the work in (126/5) hrs.
Number of days. of (42/5) hrs each =(126 x 5)/(5 x 42)=3 days

Question 7 of 20
7. Question
1 pointsfind the average of first 20 multiples of 7 ?
Correct
Incorrect
Hint

Question 8 of 20
8. Question
1 pointsThe ages of two persons differ by 16 years. If 6 years ago, the elder one be
3 times as old as the younger one, find their present ages.
Correct
correct
Incorrect
wrong
Hint
Sol. Let the age of the younger person be x years.
Then, age of the elder person = (x + 16) years.
:. 3 (x – 6) = (x + 16 – 6)
3x 18 = x + 10
2x = 28
x = 14.
Hence, their present ages are 14 years and 30 years

Question 9 of 20
9. Question
1 pointsFind the value of [ 5 ( 8^{1/3} + 27^{1/3})^{3}]^{1/ 4}
Correct
Incorrect
Hint

Question 10 of 20
10. Question
1 pointsDifference of two numbers is 1660. If 7.5% of the number is 12.5% of the other number , find the number ?
Correct
Incorrect
Hint
. Let the numbers be x and y. Then , 7.5 % of x =12.5% of y
X = 125*y/75 = 5*y/3.
Now, xy =1660
5*y/3 –y =1660
2*y/3= 1660
y =[ (1660*3)/2] =2490.
One number = 2490, Second number =5*y/3 =4150.

Question 11 of 20
11. Question
1 pointsfind S.P when CP=56.25,gain=20%.
Correct
Incorrect
Hint
SP =20% of rs 56.25 ,=rs{(120/100)*56.25}=rs67.50

Question 12 of 20
12. Question
1 pointsA bag contains 50 p, 25 P and 10 p coins in the ratio 5: 9: 4, amounting to
Rs. 206. Find the number of coins of each type.
Correct
Incorrect
Hint
Sol. Let the number of 50 p, 25 P and 10 p coins be 5x, 9x and 4x respectively.
(5x/2)+( 9x/ 4)+(4x/10)=206ó 50x + 45x + 8x = 4120ó1O3x = 4120 óx=40.
Number of 50 p coins = (5 x 40) = 200; Number of 25 p coins = (9 x 40) = 360;
Number of 10 p coins = (4 x 40) = 160

Question 13 of 20
13. Question
1 pointsA, Band C start a business each investing Rs. 20,000. After 5 months A withdrew Rs.6000 B withdrew Rs. 4000 and C invests Rs. 6000 more. At the end of the year, a total profit of Rs. 69,900 was recorded. Find the share of each.
Correct
Incorrect
Hint
Sol. Ratio of the capitals of A, Band C
= 20000 x 5 + 15000 x 7 : 20000 x 5 + 16000 x 7 : 20000 x 5 + 26000 x 7
= 205000:212000 : 282000 = 205 : 212 : 282.
A’s share = Rs. 69900 x (205/699) = Rs. 20500 I
B’s share = Rs. 69900 x (212/699) = Rs. 21200;
C’s share = Rs. 69900 x (282/699) = Rs. 28200.

Question 14 of 20
14. Question
1 pointsIf the wages of 6 men for 15 days be Rs.2100, then find the wages of
for 12 days
Correct
Incorrect
Hint
Sol. Let the required wages be Rs. x.
More men, More wages (Direct Proportion)
Less days, Less wages (Direct Proportion)
Men 6: 9 : :2100:x
Days 15:12
Therefore (6 x 15 x x)=(9 x 12 x 2100) ó x=(9 x 12 x 2100)/(6 x 15)=2520
Hence the required wages are Rs. 2520

Question 15 of 20
15. Question
1 pointsEvaluate : 6202.5 + 620.25 + 62.025 + 6.2025 + 0.62025
Correct
Incorrect
Hint
Sol. (i) 6202.5
620.25
62.025
6.2025
+ __ 0.62025
6891.59775

Question 16 of 20
16. Question
1 pointsIf two pipes function simultaneously, tbe reservoir will be filled in 12 hours. One pipe fills the reservoir 10 hours faster than tbe otber. How many hours does it take the second pipe to fill the reservoir?
Correct
Incorrect
Hint

Question 17 of 20
17. Question
1 pointsA man is standing on a railway bridge which is 180 m long. He finds that a train crosses the bridge in 20 seconds but himself in 8 seconds. Find the length of the train and its speed?
Correct
Incorrect
Hint

Question 18 of 20
18. Question
1 pointsA man can row 18 kmph in still water.it takes him thrice as long to row up as to row down the river.find the rate of stream.
Correct
Incorrect
Hint

Question 19 of 20
19. Question
1 pointsIn what ratio must water be mixed with milk to gain 20 % by selling the mixture at cost price?
Correct
Incorrect
Hint

Question 20 of 20
20. Question
1 points4/15 of 5/7 of a number is greater than 4/9 of 2/5 of the same number by 8.
What is half of that number?
Correct
Incorrect
Hint
Sol. Let the number be x. then 4/15 of 5/7 of x4/9 of 2/5 of x=8=>4/21x8/45x=8
=>(4/218/45)x=8=>(6056)/315x=8=>4/315x=8
=>x=(8*315)/4=630=>1/2x=315
Hence required number = 315
Time : 20 Minute , No of Questions20
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Question 1 of 20
1. Question
1 pointsIn one minute, a bike travels a distance of 550 meters whereas a car travels a distance of 33 km in 45 minutes. What is the ratio of their speed?
Correct
correct
Incorrect
wrong
Hint
Ratio of speeds =
550
60x 18
5:
33
45x60 = 33 : 44 = 3 : 4

Question 2 of 20
2. Question
1 pointsFind the L.C.M. of 2^{2} x 3^{3} x 5 x 7^{2 , }2^{3} x 3^{2 }x 5^{2} x 7^{4 } , 2 x 3 x 5^{3 x 7 x 11.}
Correct
correct
Incorrect
wrong
Hint
L.C.M. = Product of highest powers of 2, 3, 5, 7 and 11 = 2^{3} x 3^{3} x 5^{3} x 7^{4 }x 11

Question 3 of 20
3. Question
1 pointsA is twice as good a workman as B and together they finish a piece in 18 days. In how many days will A alone finish the work?
Correct
Incorrect
Hint
(A’s 1 day’s work):)(B’s 1 days work) = 2 : 1.
(A + B)’s 1 day’s work = 1/18
Divide 1/18 in the ratio 2 : 1.
A’s 1 day’s work =(1/18*2/3)=1/27
Hence, A alone can finish the work in 27 days.

Question 4 of 20
4. Question
1 pointsThere are two sections A and B of a class consisting of 36 and 44 students respectively. If the average weight of section A is 40kg and that of section B is 35kg, find the average weight of the whole class?
Correct
Incorrect
Hint

Question 5 of 20
5. Question
1 pointsThe present age of a father is 3 years more than three times the age of his son. Three years hence, father’s age will be 10 years more than twice the age of the son. Find the present age of the father.
Correct
correct
Incorrect
wrong
Hint

Question 6 of 20
6. Question
1 pointsIf (1/5)^{3y} = 0.008, then find the value of(0.25)^{y}
Correct
Incorrect
Hint

Question 7 of 20
7. Question
1 pointsIn an election between two candidates, 75% of the voters cast thier thier votes, out of which 2% of the votes were declared invalid. A candidate got 9261 votes which were 75% of the total valid votes. Find the total number of votes enrolled in that election
Correct
Incorrect
Hint
Let the number of votes enrolled be x. Then ,
Number of votes cast =75% of x. Valid votes = 98% of (75% of x).
75% of (98% of (75%of x)) =9261.
[(75/100)*(98/100)*(75/100)*x] =9261.
X = [(9261*100*100*100)/(75*98*75)] =16800.

Question 8 of 20
8. Question
1 pointsA person incures loss for by selling a watch for rs1140.at what price should the watch be sold to earn a 5% profit ?
Correct
Incorrect
Hint
sol. let the new sp be rsx.then
(100loss%) : (1^{st} sp)=(100+gain%) (2^{nd} sp)
 {(1005)/1400}={(100+5)/x}=> x={(105*1140)/95} =1260.

Question 9 of 20
9. Question
1 pointsFour milkmen rented a pasture. A grazed 24 cows for 3 months; B 10 for 5 months; C 35 cows for 4 months and D 21 cows for 3 months. If A’s share of rent is Rs. 720, find the total rent of the field.
Correct
Incorrect
Hint
Sol. Ratio of shares of A, B, C, D = (24 x 3) : (10 x 5) : (35 x 4) : (21 x 3) = 72 : 50 : 140 : 63.
Let total rent be Rs. x. Then, A’s share = Rs. (72x)/325
(72x)/325=720 ó x=(720 x 325)/72 = 3250
Hence, total rent of the field is Rs. 3250

Question 10 of 20
10. Question
1 pointsIf 15 men, working 9 hours a day, can reap a field in 16 days, in how many
days will 18 men reap the field, working 8 hours a day?
Correct
Incorrect
Hint
Sol. Let the required number of days be x.
More men, Less days (indirect proportion)
Less hours per day, More days (indirect proportion)
Men 18 : 15
Hours per day 8: 9 } : :16 : x
(18 x 8 x x)=(15 x 9 x 16)ó x=(44 x 15)144 = 15
Hence, required number of days = 15

Question 11 of 20
11. Question
1 pointsAn electric pump can fill a tank in 3 hours. Because of a leak in ,the tank it took 3(1/2) hours to fill the tank. If the tank is full, how much time will the leak take to empty it ?
Correct
Incorrect
Hint
Sol: work done by the leak in 1 hour=(1/3)(1/(7/2))=(1/3)(2/7)=(1/21).
The leak will empty .the tank in 21 hours.

Question 12 of 20
12. Question
1 pointsA train 220 m long is running with a speed of 59 kmph.. In what will it pass a man who is running at 7 kmph in the direction opposite to that in which the train is going?
Correct
Incorrect
Hint

Question 13 of 20
13. Question
1 pointsA man can row 7 ½ kmph in still water.if in a river running at 1.5 km/hr an hour,it takes him 50 minutes to row to a place and back,how far off is the place?
Correct
Incorrect
Hint

Question 14 of 20
14. Question
1 pointsThe milk and water in two vessels A and B are in the ratio 4 : 3 and 2: 3 respectively. In what ratio, the liquids in both the vessels be mixed to obtain a new mixture in vessel C containing half milk and half water?
Correct
Incorrect
Hint

Question 15 of 20
15. Question
1 pointsAdam borrowed some money at the rate of 6% p.a. for the first two years , at the rate of 9% p.a. for the next three years , and at the rate of 14% p.a. for the period beyond five years. 1£ he pays a total interest of Rs. 11, 400 at the end of nine years how much money did he borrow ?
Correct
Incorrect

Question 16 of 20
16. Question
1 pointsIf the simple interest on a sum of money at 5% per annum for 3 years is Rs. 1200, find the compound interest on the same sum for the same period at the same rate.
Correct
Incorrect
Hint

Question 17 of 20
17. Question
1 pointsCorrect
Incorrect
Hint
Sol. Given exp.= 108¸9+2*13 =108 +13 =12+13 =133 = 13 3
5 4 9 10 10 10 10

Question 18 of 20
18. Question
1 pointsThe length of a rectangle is twice its breadth. If its length is decreased by 5 cm and breadth is increased by 5 cm, the area of the rectangle is increased by 75 sq. cm. Find the length of the rectangle.
Correct
Incorrect
Hint
Sol. Let breadth = x. Then, length = 2x. Then,
(2x – 5) (x + 5) – 2x * x = 75 <=> 5x – 25 = 75 <=> x = 20.
:. Length of the rectangle = 20 cm.

Question 19 of 20
19. Question
1 pointsWater flows into a tank 200 m x 160 m througb a rectangular pipe of 1.5m x 1.25 m @ 20 kmph . In what time (in minutes) will the water rise by 2 meters ?
Correct
Incorrect
Hint
Sol. Volume required in the tank = (200 x 150 x 2) m^{3} = 60000 m^{3}.
Length of water column flown in1 min =(20*1000)/60 m =1000/3 m
Volume flown per minute = 1.5 * 1.25 * (1000/3) m^{3} = 625 m^{3}.
Required time = (60000/625)min = 96min

Question 20 of 20
20. Question
1 pointsEx. 5. A, Band C are three contestants in a km race. If A can give B a start of 40 m
and A can give C a start of 64m how many metre’s start can B give C ?
Correct
Incorrect
Hint
Sol: While A covers 1000 m, B covers (1000 – 40) m = 960 m and
C covers (1000 – 64) m or 936 m.
When B covers 960 m, C covers 936 m.
Time : 20 Minute , No of Questions20
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Aptitude Online Test Set 6
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Question 1 of 20
1. Question
1 pointsBikash is running at a speed of 6 km/hr crosses a flyover in 18 minutes. What is the length of the flyover (in meters)?
Correct
correct
Incorrect
wrong
Hint
Rohan’s speed = 6 km/hr = 6x
5
18m/sec =
5
3m/sec
Length of the flyover =
5
3x18x60 = 1800 m

Question 2 of 20
2. Question
1 pointsA can do a certain job in 12 days. B is 60% more efficient than A. How many days does B alone take to do the same job?
Correct
Incorrect
Hint
Ratio of times taken by A and B = 160 : 100 = 8 : 5.
Suppose B alone takes x days to do the job.
Then, 8 : 5 :: 12 : x
8x = 5 x 12 =60
x = 15/2 days.

Question 3 of 20
3. Question
1 pointsNine persons went to a hotel for taking their meals 8 of them spent Rs.12 each on their meals and the ninth spent Rs.8 more than the average expenditure of all the nine.What was the total money spent by them?
Correct
Incorrect

Question 4 of 20
4. Question
1 points. Rohit was 4 times as old as his son 8 years ago. After 8 years, Rohit will be
twice as old as his son. What are their present ages?
Correct
correct
Incorrect
wrong

Question 5 of 20
5. Question
1 pointsCorrect
Incorrect
Hint

Question 6 of 20
6. Question
1 pointsShobha’s mathematics test had 75 problems i.e.10 arithmetic, 30 algebra and 35 geometry problems. Although she answered 70% of the arithmetic ,40% of the algebra, and 60% of the geometry problems correctly. she did not pass the test because she got less than 60% of the problems right. How many more questions she would have to answer correctly to earn 60% of the passing grade?
Correct
Incorrect
Hint
Sol. Number of questions attempted correctly=(70% of 10 + 40% of 30 + 60% 0f 35)
=7 + 12+21= 45
questions to be answered correctly for 60% grade=60% of 75 = 45
therefore required number of questions= (4540) = 5

Question 7 of 20
7. Question
1 pointsA book was sold for rs 27.50 with a profit of 10%. if it were sold for rs25.75, then what would be % of profit or loss?
Correct
Incorrect
Hint
sol. SP=rs 27.50: profit =10%.
CP=rs {(100/110)*27.50}=rs 25.
When sp =Rs25.75 ,profit =Rs(25.7525)=Rs 0.75
Profit%={(0.75/25)*100}%=25/6%=3%

Question 8 of 20
8. Question
1 pointsA invested Rs. 76,000 in a business. After few months, B joined him Rs. 57,000. At the end of the year, the total profit was divided between them in ratio 2 : 1. After bow many months did B join?
Correct
Incorrect
Hint
Sol. Suppose B joined after x months. Then, B’s money was invested for (12 – x)
(76000 x 12)/(57000 x (12x) =2/1 ó 912000=114000(12x)
114 (12 – x) = 912ó12x=8óx=4
Hence, B joined after 4 months.

Question 9 of 20
9. Question
1 pointsIf 9 engines consume 24 metric tonnes of coal, when each is working 8 hours day, bow much coal will be required for 8 engines, each running 13hours a day, it being given that 3 engines of former type consume as much as 4 engines of latter type?
Correct
Incorrect
Hint
Sol. Let 3 engines of former type consume 1 unit in 1 hour.
Then, 4 engines of latter type consume 1 unit in 1 hour.
Therefore 1 engine of former type consumes(1/3) unit in 1 hour.1 engine of latter type consumes(1/4) unit in 1 hour.
Let the required consumption of coal be x units.
Less engines, Less coal consumed (direct proportion)
More working hours, More coal consumed (direct proportion)
Less rate of consumption, Less coal consumed(direct prportion)Number of engines 9: 8
Working hours 8 : 13 } :: 24 : x
Rate of consumption (1/3):(1/4)
[ 9 x 8 x (1/3) x x) = (8 x 13 x (1/4) x 24 ) => 24x = 624 => x = 26.
Hence, the required consumption of coal = 26 metric tonnes 
Question 10 of 20
10. Question
1 pointsWhat value will replace the question mark in the following equations ?
 ? – 7328.96 + 5169.38
Correct
Incorrect
Hint
Let x – 7328.96 = 5169.38. Then, x = 5169.38 + 7328.96 = 12498.34

Question 11 of 20
11. Question
1 pointsTwo pipes can fill a cistern in 14 hours and 16 hours respectively. The pipes are opened simultaneously and it is found that due to leakage in the bottom it took 32 minutes more to fill the cistern.When the cistern is full, in what time will the leak empty it?
Correct
Incorrect
Hint
Sol: Work done by the two pipes in 1 hour =(1/14)+(1/16)=(15/112).
Time taken by these pipes to fill the tank = (112/15) hrs = 7 hrs 28 min.
Due to leakage, time taken = 7 hrs 28 min + 32 min = 8 hrs
Work done by (two pipes + leak) in 1 hour = (1/8).
Work done by the leak m 1 hour =(15/112)(1/8)=(1/112).
Leak will empty the full cistern in 112 hours.

Question 12 of 20
12. Question
1 pointsTwo trains 137 meters and 163 meters in length are running towards each other on parallel lines, one at the rate of 42 kmph and another at 48 kmph. In what time will they be clear of each other from the moment they meet?
Correct
Incorrect
Hint

Question 13 of 20
13. Question
1 pointsIn a stream running at 2 kmph,a motor boat goes 6 km upstream and back again to the starting point in 33 minutes.find the speed of the motor boat in still water.
Correct
Incorrect
Hint

Question 14 of 20
14. Question
1 pointsA certain sum of money amounts to Rs. 1008 in 2 years and to Rs.1164 in 3 ½ years. Find the sum and rate of interests.
Correct
Incorrect
Hint

Question 15 of 20
15. Question
1 pointsIn what time will Rs. 1000 become Rs. 1331 at 10% per annum compounded annually?
Correct
Incorrect
Hint

Question 16 of 20
16. Question
1 pointsSimplify: 12.05*5.4+0.6
Correct
Incorrect
Hint
Sol. Given exp. = 12.05*(5.4/0.6) = (12.05*9) = 108.45

Question 17 of 20
17. Question
1 pointsIn measuring the sides of a rectangle, one side is taken 5% in excess, and the other 4% in deficit. Find the error percent in the area calculated from these measurements.
Correct
Incorrect
Hint
Sol. Let x and y be the sides of the rectangle. Then, Correct area = xy.
Calculated area = (105/100)*x * (96/100)*y = (504/500 )(xy)
Error In measurement = (504/500)xy xy = (4/500)xy
Error % = [(4/500)xy *(1/xy) *100] % = (4/5) % = 0.8%.

Question 18 of 20
18. Question
1 pointsTbe dimensions of an open box are 50 cm, 40 cm and 23 cm. Its thickness is 2 cm. If 1 cubic cm of metal used in the box weighs 0.5 gms, find the weight of the box.
Correct
Incorrect
Hint
Sol. Volume of the metal used in the box = External Volume – Internal Volume
= [(50 * 40 * 23) – (44 * 34 * 20)]cm^{3}
= 16080 cm^{3}
Weight of the metal =((16080*0.5)/1000) kg = 8.04 kg.

Question 19 of 20
19. Question
1 pointsEx 6. In a game of 80 points; A can give B 5 points and C 15 points. Then how many points B can give C in a game of 60 ?
Correct
Incorrect
Hint
Sol. A: B = 80 : 75, A : C = 80 : 65.
B/C = ( B/ A * A/C) = (75 / 80 * 80 / 65) = 15/13 = 60 /52 = 60: 5
Therfore ,In a game of 60, B can give C 8 points.

Question 20 of 20
20. Question
1 pointsThe last day of a century cannot be :
Correct
Incorrect
Hint
100 years contains 5 odd day
=> last day of first century is friday .
200 years contains (5*2)=10/7= 3 odd day
=>last day of 2nd century is wednesday.
300 years contains(5*3)=15/7= 1 odd day .
=>last day of 3rd century is monday.
400 years contain 0 odd day.
=> last day of 4th century is sunday
this cycle is repeated.
=>last day of century cannot be tuesday or thursday or saturday .
Time : 20 Minute , No of Questions20
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Aptitude Online Test Set 7
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Question 1 of 20
1. Question
1 pointsTom left for Delhi from Jaipur at 6 AM. For 2 hours, she traveled at the rate of 80 km/hr. After that, she reduced her speed to 60 km/hr. If the distance between two cities is 400 km, find the time when Tom will reach Delhi?
Correct
correct
Incorrect
wrong
Hint
Distance covered in 2 hours = 80 x 2 = 160 km
Time taken to cover the remaining distance =(400 – 160)
60=
240
60hrs = 4 hrs
Total time taken = 2 + 4 = 6 hrs
Ankita will reach Delhi at 12:00 P.M. 
Question 2 of 20
2. Question
1 pointsA can do a piece of work in 80 days. He works at it for 10 days B alone finishes the remaining work in 42 days. In how much time will A and B working together, finish the work?